The sixth and final matchday of the UEFA Champions League will see Borussia Dortmund play host to 2020 finalists, Paris Saint-Germain, on Wednesday. The French outfit could still finish first, second or third in the group, while BVB have already booked their place in the round of 16.

The scenario

  • Borussia Dortmund and Paris Saint-Germain are going head-to-head in European competition for the sixth time. There has been one win, two draws and two defeats – including the 2-0 loss at the Parc des Princes on Matchday 1 due to goals from Kylian Mbappé (pen., 49) and Achraf Hakimi (58).
  • In Dortmund, there has been one draw (1-1 in the UEFA Europa League in the 2010/11 season, goal from Nuri Sahin) and a 2-1 victory in the 2019/20 UEFA Champions League round of 16 first leg (both goals from Erling Haaland).
  • Borussia Dortmund would secure top spot in the group with a draw. Paris Saint-Germain, meanwhile, need a victory to finish in top spot and avoid potentially being eliminated from the competition entirely. Because a draw would leave the French team on eight points, which is what Newcastle would have if they beat Milan. The English club would then have the superior head-to-head record. If PSG were to lose in Dortmund, they would be overtaken by the winner of the Newcastle-Milan game.

BVB facts

  • Borussia Dortmund qualified for the knockout stages for the fifth time in the last six years courtesy of their 3-1 victory away to AC Milan.
  • The Black & Yellows were unbeaten in their first six home games against French clubs (three wins, three draws). The overall record in their own stadium stands at six wins, three draws and two defeats. 
  • BVB have lost only one of their last 17 home matches in the group phase of the UEFA Champions League (10 wins and six draws).

PSG facts

  • The French side have managed only one win in their last six visits to Germany (three years ago in Munich); they have also drawn one match and suffered four defeats.
  • PSG have consistently reached the knockouts since 2012/13.